🫏 Oblicz 1 1 3 X 2 5
Two numbers r and s sum up to -3 exactly when the average of the two numbers is \frac{1}{2}*-3 = -\frac{3}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C.
Combining like terms yields. x - 2 = 10. Adding 2 to each member yields. x-2+2 =10+2. x = 12. To solve an equation, we use the addition-subtraction property to transform a given equation to an equivalent equation of the form x = a, from which we can find the solution by inspection. Example 3 Solve 2x + 1 = x - 2.
Question: Evaluate the following definite integral: Z 3 1 (2x − 1 + 3 x − 5 x 2 ) dx. (b) Simplify: d dx Z x 5 −2018 cos (t 4 ) dt. (c) Evaluate the following
To write −12 5 - 12 5 as a fraction with a common denominator, multiply by 3 3 3 3. 10 3 ⋅ 5 5 − 12 5 ⋅ 3 3 10 3 ⋅ 5 5 - 12 5 ⋅ 3 3. Write each expression with a common denominator of 15 15, by multiplying each by an appropriate factor of 1 1. Tap for more steps 10⋅5 15 − 12⋅3 15 10 ⋅ 5 15 - 12 ⋅ 3 15. Combine the
Simplify x^ (1/2)*x^ (1/3) x1 2 ⋅ x1 3 x 1 2 ⋅ x 1 3. Use the power rule aman = am+n a m a n = a m + n to combine exponents. x1 2+1 3 x 1 2 + 1 3. To write 1 2 1 2 as a fraction with a common denominator, multiply by 3 3 3 3. x1 2⋅3 3+1 3 x 1 2 ⋅ 3 3 + 1 3.
Algebra. Expand Using the Binomial Theorem (1-x)^3. (1 − x)3 ( 1 - x) 3. Use the binomial expansion theorem to find each term. The binomial theorem states (a+b)n = n ∑ k=0nCk⋅(an−kbk) ( a + b) n = ∑ k = 0 n n C k ⋅ ( a n - k b k). 3 ∑ k=0 3! (3− k)!k! ⋅(1)3−k ⋅(−x)k ∑ k = 0 3 3! ( 3 - k)! k! ⋅ ( 1) 3 - k ⋅ ( - x) k
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